(2x+1)(3x^2+x+5)=

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Solution for (2x+1)(3x^2+x+5)= equation: 


Simplifying
(2x + 1)(3x2 + x + 5) = 0

Reorder the terms:
(1 + 2x)(3x2 + x + 5) = 0

Reorder the terms:
(1 + 2x)(5 + x + 3x2) = 0

Multiply (1 + 2x) * (5 + x + 3x2)
(1(5 + x + 3x2) + 2x * (5 + x + 3x2)) = 0
((5 * 1 + x * 1 + 3x2 * 1) + 2x * (5 + x + 3x2)) = 0
((5 + 1x + 3x2) + 2x * (5 + x + 3x2)) = 0
(5 + 1x + 3x2 + (5 * 2x + x * 2x + 3x2 * 2x)) = 0
(5 + 1x + 3x2 + (10x + 2x2 + 6x3)) = 0

Reorder the terms:
(5 + 1x + 10x + 3x2 + 2x2 + 6x3) = 0

Combine like terms: 1x + 10x = 11x
(5 + 11x + 3x2 + 2x2 + 6x3) = 0

Combine like terms: 3x2 + 2x2 = 5x2
(5 + 11x + 5x2 + 6x3) = 0

Solving
5 + 11x + 5x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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